Java使用5个线程计算数组之和

网友投稿 295 2022-10-24


Java使用5个线程计算数组之和

前言

之前写过多线程累加计数,原理跟本篇类似,传送门

累加计数比计算数组之和逻辑稍微简单一点,如果对于这块不熟悉的,可以先看下累加计数。

基本思想已经在之前那篇文章里写过了,这里就直接贴代码了。

这里分别通过自己创建线程来实现功能,还有通过线程池来实现功能。思想都差不多。只是代码写法略有不同。仅供参考。

代码一:

五个线程交替累加计算数组之和,这种方法其实不如单线程直接累加快,因为交替累加需要前一个线程计算的结果。

package test;

import java.util.concurrent.ExecutorService;

import java.util.concurrent.Executors;

public class FiveThreadCount {

private int count=0;

private int[] arr={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28};

private int j=0;

//定义一个任务,关键点所在

private class MyThread extends Thread{

@Override

public void run() {

super.run();

while(j

{

synchronized (MyThread.class) {

if(j>=arr.length){

return;

}

count+=arr[j++];

try {

Thread.sleep(100);

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

System.out.println(Thread.currentThread().getName());

}

}

}

}

//方法一

public void test1(){

for(int i=0;i<5;i++){

new MyThread().start();

}

try {

Thread.sleep(10000);

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

System.out.println(count);

}

//方法二

public void test2(){

Thread myThread=new MyThread();

for(int i=0;i<5;i++){

new Thread(myThread).start();

}

try {

Thread.sleep(10000);

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

System.out.println(count);

}

//方法一的线程池实现版

public void test3(){

ExecutorService service=Executors.newCachedThreadPool();

for(int i=0;i<5;i++){

service.execute(new MyThread());

}

try {

Thread.sleep(10000);

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

System.out.println(count);

}

//方法二的线程池实现版

public void test4(){

ExecutorService service=Executors.newCachedThreadPool();

Thread myThread=new MyThread();

for(int i=0;i<5;i++){

service.execute(myThread);

}

try {

Thread.sleep(10000);

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

System.out.println(count);

}

}

上边代码中,用到了sleep方法的原因,sleep(100)是为了让其他线程有时间执行任务,如果不sleep的话,有可能一个线程就全部执行完了。 最后的sleep(10000)是为了等所有线程执行完后,打印最后的计算结果。

代码二:

将数组分为5等分,让每个线程计算自己负责的那份,并发计算,最后汇总结果。这种方式比代码一速度会快些。因为线程独立计算,不依赖其他线程的结果。最后几个线程将总数累加即可。

方式一:

使用Callable,FutureTask方式,来实现代码:

package test;

import java.util.concurrent.Callable;

import java.util.concurrent.ExecutionException;

import java.util.concurrent.ExecutorService;

import java.util.concurrent.Executors;

import java.util.concurrent.FutureTask;

public class FiveThreadCount2 {

private int[] arr={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28};

private int total=0;

public void test() throws InterruptedException, ExecutionException{

ExecutorService service=Executors.newFixedThreadPool(5);

int length=arr.length;

for(int j=0;j

FutureTask task;

if( (j+(length/5))

task=new FutureTask(new MyCallable(arr, j, j+(length/5)));

}else{

task=new FutureTask(new MyCallable(arr, j, length));

}

service.execute(task);

total+=task.get();

}

service.shutdown();

System.out.println(total);

}

public class MyCallable implements Callable{

int[] arr;

int startIndex;

int endIndex;

public MyCallable(int[] arr,int startIndex,int endIndex){

this.arr=arr;

this.startIndex=startIndex;

this.endIndex=endIndex;

}

@Override

public Integer call() throws Exception {

int sum=0;

for(int i=startIndex;i

sum+=arr[i];

}

System.out.println(Thread.currentThread().getName());

return sum;

}

}

}

这个方式有一个缺点,看似5个线程异步执行,其实是顺序执行,因为 task.get是要等待线程执行完毕才会执行下边的代码。所以效率不会高,可能换种写法可以解决这个问题,这里就不深入研究。

方式二:

通过java工具类CountDownLatch实现并发计算

package test;

import java.util.concurrent.CountDownLatch;

public class FiveThreadCount3 {

private int[] arr={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28};

private int total=0;

public void test() throws InterruptedException{

int length=arr.length;

CountDownLatch latch=new CountDownLatch(length%5==0?5:6);

System.out.println(length);

for(int j=0;j

MyThread task;

if( (j+(length/5))<=length){

task=new MyThread(arr, j, j+(length/5), latch);

}else{

task=new MyThread(arr, j, length, latch);

}

new Thread(task).start();

}

latch.await();

System.out.println(total);

}

private class MyThread implements Runnable{

int[] arr;

int startIndex;

int endIndex;

CountDownLatch latch;

public MyThread(int[] arr,int startIndex,int endIndex,CountDownLatch latch){

this.arr=arr;

this.startIndex=startIndex;

this.endIndex=endIndex;

this.latch=latch;

}

@Override

public void run() {

int sum=0;

for(int i=startIndex;i

sum+=arr[i];

}

synchronized (MyThread.class) {

total+=sum;

}

System.out.println(Thread.currentThread().getName());

latch.countDown();

}

}

}

对于CountDownLatch不熟悉的可以搜索下用法。

方式三:

通过java工具类 CyclicBarrier实现并发计算。

package test;

import java.util.concurrent.BrokenBarrierException;

import java.util.concurrent.CyclicBarrier;

public class FiveThreadCount1 {

private int[] arr={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28};

private int total=0;

public void test() throws InterruptedException, BrokenBarrierException{

int length=arr.length;

CyclicBarrier barrier=new CyclicBarrier((length%5==0?5:6)+1);

System.out.println(length);

for(int j=0;j

MyThread task;

if( (j+(length/5))<=length){

task=new MyThread(arr, j, j+(length/5), barrier);

}else{

task=new MyThread(arr, j, length, barrier);

}

new Thread(task).start();

}

barrier.await();

System.out.println(total);

}

private class MyThread implements Runnable{

int[] arr;

int startIndex;

int endIndex;

CyclicBarrier barrier;

public MyThread(int[] arr,int startIndex,int endIndex,CyclicBarrier barrier){

this.arr=arr;

this.startIndex=startIndex;

this.endIndex=endIndex;

this.barrier=barrier;

}

@Override

public void run() {

int sum=0;

for(int i=startIndex;i

sum+=arr[i];

}

synchronized (MyThread.class) {

total+=sum;

}

try {

System.out.println(Thread.currentThread().getName());

barrier.await();

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

} catch (BrokenBarrierException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

}

}

}

总结

总体来说,代码二的方式二、三,效率会高一点。以上代码都是通过main方法调用示例代码的test方法,输出结果到控制台。

{

synchronized (MyThread.class) {

if(j>=arr.length){

return;

}

count+=arr[j++];

try {

Thread.sleep(100);

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

System.out.println(Thread.currentThread().getName());

}

}

}

}

//方法一

public void test1(){

for(int i=0;i<5;i++){

new MyThread().start();

}

try {

Thread.sleep(10000);

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

System.out.println(count);

}

//方法二

public void test2(){

Thread myThread=new MyThread();

for(int i=0;i<5;i++){

new Thread(myThread).start();

}

try {

Thread.sleep(10000);

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

System.out.println(count);

}

//方法一的线程池实现版

public void test3(){

ExecutorService service=Executors.newCachedThreadPool();

for(int i=0;i<5;i++){

service.execute(new MyThread());

}

try {

Thread.sleep(10000);

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

System.out.println(count);

}

//方法二的线程池实现版

public void test4(){

ExecutorService service=Executors.newCachedThreadPool();

Thread myThread=new MyThread();

for(int i=0;i<5;i++){

service.execute(myThread);

}

try {

Thread.sleep(10000);

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

System.out.println(count);

}

}

上边代码中,用到了sleep方法的原因,sleep(100)是为了让其他线程有时间执行任务,如果不sleep的话,有可能一个线程就全部执行完了。 最后的sleep(10000)是为了等所有线程执行完后,打印最后的计算结果。

代码二:

将数组分为5等分,让每个线程计算自己负责的那份,并发计算,最后汇总结果。这种方式比代码一速度会快些。因为线程独立计算,不依赖其他线程的结果。最后几个线程将总数累加即可。

方式一:

使用Callable,FutureTask方式,来实现代码:

package test;

import java.util.concurrent.Callable;

import java.util.concurrent.ExecutionException;

import java.util.concurrent.ExecutorService;

import java.util.concurrent.Executors;

import java.util.concurrent.FutureTask;

public class FiveThreadCount2 {

private int[] arr={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28};

private int total=0;

public void test() throws InterruptedException, ExecutionException{

ExecutorService service=Executors.newFixedThreadPool(5);

int length=arr.length;

for(int j=0;j

FutureTask task;

if( (j+(length/5))

task=new FutureTask(new MyCallable(arr, j, j+(length/5)));

}else{

task=new FutureTask(new MyCallable(arr, j, length));

}

service.execute(task);

total+=task.get();

}

service.shutdown();

System.out.println(total);

}

public class MyCallable implements Callable{

int[] arr;

int startIndex;

int endIndex;

public MyCallable(int[] arr,int startIndex,int endIndex){

this.arr=arr;

this.startIndex=startIndex;

this.endIndex=endIndex;

}

@Override

public Integer call() throws Exception {

int sum=0;

for(int i=startIndex;i

sum+=arr[i];

}

System.out.println(Thread.currentThread().getName());

return sum;

}

}

}

这个方式有一个缺点,看似5个线程异步执行,其实是顺序执行,因为 task.get是要等待线程执行完毕才会执行下边的代码。所以效率不会高,可能换种写法可以解决这个问题,这里就不深入研究。

方式二:

通过java工具类CountDownLatch实现并发计算

package test;

import java.util.concurrent.CountDownLatch;

public class FiveThreadCount3 {

private int[] arr={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28};

private int total=0;

public void test() throws InterruptedException{

int length=arr.length;

CountDownLatch latch=new CountDownLatch(length%5==0?5:6);

System.out.println(length);

for(int j=0;j

MyThread task;

if( (j+(length/5))<=length){

task=new MyThread(arr, j, j+(length/5), latch);

}else{

task=new MyThread(arr, j, length, latch);

}

new Thread(task).start();

}

latch.await();

System.out.println(total);

}

private class MyThread implements Runnable{

int[] arr;

int startIndex;

int endIndex;

CountDownLatch latch;

public MyThread(int[] arr,int startIndex,int endIndex,CountDownLatch latch){

this.arr=arr;

this.startIndex=startIndex;

this.endIndex=endIndex;

this.latch=latch;

}

@Override

public void run() {

int sum=0;

for(int i=startIndex;i

sum+=arr[i];

}

synchronized (MyThread.class) {

total+=sum;

}

System.out.println(Thread.currentThread().getName());

latch.countDown();

}

}

}

对于CountDownLatch不熟悉的可以搜索下用法。

方式三:

通过java工具类 CyclicBarrier实现并发计算。

package test;

import java.util.concurrent.BrokenBarrierException;

import java.util.concurrent.CyclicBarrier;

public class FiveThreadCount1 {

private int[] arr={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28};

private int total=0;

public void test() throws InterruptedException, BrokenBarrierException{

int length=arr.length;

CyclicBarrier barrier=new CyclicBarrier((length%5==0?5:6)+1);

System.out.println(length);

for(int j=0;j

MyThread task;

if( (j+(length/5))<=length){

task=new MyThread(arr, j, j+(length/5), barrier);

}else{

task=new MyThread(arr, j, length, barrier);

}

new Thread(task).start();

}

barrier.await();

System.out.println(total);

}

private class MyThread implements Runnable{

int[] arr;

int startIndex;

int endIndex;

CyclicBarrier barrier;

public MyThread(int[] arr,int startIndex,int endIndex,CyclicBarrier barrier){

this.arr=arr;

this.startIndex=startIndex;

this.endIndex=endIndex;

this.barrier=barrier;

}

@Override

public void run() {

int sum=0;

for(int i=startIndex;i

sum+=arr[i];

}

synchronized (MyThread.class) {

total+=sum;

}

try {

System.out.println(Thread.currentThread().getName());

barrier.await();

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

} catch (BrokenBarrierException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

}

}

}

总结

总体来说,代码二的方式二、三,效率会高一点。以上代码都是通过main方法调用示例代码的test方法,输出结果到控制台。

FutureTask task;

if( (j+(length/5))

task=new FutureTask(new MyCallable(arr, j, j+(length/5)));

}else{

task=new FutureTask(new MyCallable(arr, j, length));

}

service.execute(task);

total+=task.get();

}

service.shutdown();

System.out.println(total);

}

public class MyCallable implements Callable{

int[] arr;

int startIndex;

int endIndex;

public MyCallable(int[] arr,int startIndex,int endIndex){

this.arr=arr;

this.startIndex=startIndex;

this.endIndex=endIndex;

}

@Override

public Integer call() throws Exception {

int sum=0;

for(int i=startIndex;i

sum+=arr[i];

}

System.out.println(Thread.currentThread().getName());

return sum;

}

}

}

这个方式有一个缺点,看似5个线程异步执行,其实是顺序执行,因为 task.get是要等待线程执行完毕才会执行下边的代码。所以效率不会高,可能换种写法可以解决这个问题,这里就不深入研究。

方式二:

通过java工具类CountDownLatch实现并发计算

package test;

import java.util.concurrent.CountDownLatch;

public class FiveThreadCount3 {

private int[] arr={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28};

private int total=0;

public void test() throws InterruptedException{

int length=arr.length;

CountDownLatch latch=new CountDownLatch(length%5==0?5:6);

System.out.println(length);

for(int j=0;j

MyThread task;

if( (j+(length/5))<=length){

task=new MyThread(arr, j, j+(length/5), latch);

}else{

task=new MyThread(arr, j, length, latch);

}

new Thread(task).start();

}

latch.await();

System.out.println(total);

}

private class MyThread implements Runnable{

int[] arr;

int startIndex;

int endIndex;

CountDownLatch latch;

public MyThread(int[] arr,int startIndex,int endIndex,CountDownLatch latch){

this.arr=arr;

this.startIndex=startIndex;

this.endIndex=endIndex;

this.latch=latch;

}

@Override

public void run() {

int sum=0;

for(int i=startIndex;i

sum+=arr[i];

}

synchronized (MyThread.class) {

total+=sum;

}

System.out.println(Thread.currentThread().getName());

latch.countDown();

}

}

}

对于CountDownLatch不熟悉的可以搜索下用法。

方式三:

通过java工具类 CyclicBarrier实现并发计算。

package test;

import java.util.concurrent.BrokenBarrierException;

import java.util.concurrent.CyclicBarrier;

public class FiveThreadCount1 {

private int[] arr={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28};

private int total=0;

public void test() throws InterruptedException, BrokenBarrierException{

int length=arr.length;

CyclicBarrier barrier=new CyclicBarrier((length%5==0?5:6)+1);

System.out.println(length);

for(int j=0;j

MyThread task;

if( (j+(length/5))<=length){

task=new MyThread(arr, j, j+(length/5), barrier);

}else{

task=new MyThread(arr, j, length, barrier);

}

new Thread(task).start();

}

barrier.await();

System.out.println(total);

}

private class MyThread implements Runnable{

int[] arr;

int startIndex;

int endIndex;

CyclicBarrier barrier;

public MyThread(int[] arr,int startIndex,int endIndex,CyclicBarrier barrier){

this.arr=arr;

this.startIndex=startIndex;

this.endIndex=endIndex;

this.barrier=barrier;

}

@Override

public void run() {

int sum=0;

for(int i=startIndex;i

sum+=arr[i];

}

synchronized (MyThread.class) {

total+=sum;

}

try {

System.out.println(Thread.currentThread().getName());

barrier.await();

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

} catch (BrokenBarrierException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

}

}

}

总结

总体来说,代码二的方式二、三,效率会高一点。以上代码都是通过main方法调用示例代码的test方法,输出结果到控制台。

task=new FutureTask(new MyCallable(arr, j, j+(length/5)));

}else{

task=new FutureTask(new MyCallable(arr, j, length));

}

service.execute(task);

total+=task.get();

}

service.shutdown();

System.out.println(total);

}

public class MyCallable implements Callable{

int[] arr;

int startIndex;

int endIndex;

public MyCallable(int[] arr,int startIndex,int endIndex){

this.arr=arr;

this.startIndex=startIndex;

this.endIndex=endIndex;

}

@Override

public Integer call() throws Exception {

int sum=0;

for(int i=startIndex;i

sum+=arr[i];

}

System.out.println(Thread.currentThread().getName());

return sum;

}

}

}

这个方式有一个缺点,看似5个线程异步执行,其实是顺序执行,因为 task.get是要等待线程执行完毕才会执行下边的代码。所以效率不会高,可能换种写法可以解决这个问题,这里就不深入研究。

方式二:

通过java工具类CountDownLatch实现并发计算

package test;

import java.util.concurrent.CountDownLatch;

public class FiveThreadCount3 {

private int[] arr={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28};

private int total=0;

public void test() throws InterruptedException{

int length=arr.length;

CountDownLatch latch=new CountDownLatch(length%5==0?5:6);

System.out.println(length);

for(int j=0;j

MyThread task;

if( (j+(length/5))<=length){

task=new MyThread(arr, j, j+(length/5), latch);

}else{

task=new MyThread(arr, j, length, latch);

}

new Thread(task).start();

}

latch.await();

System.out.println(total);

}

private class MyThread implements Runnable{

int[] arr;

int startIndex;

int endIndex;

CountDownLatch latch;

public MyThread(int[] arr,int startIndex,int endIndex,CountDownLatch latch){

this.arr=arr;

this.startIndex=startIndex;

this.endIndex=endIndex;

this.latch=latch;

}

@Override

public void run() {

int sum=0;

for(int i=startIndex;i

sum+=arr[i];

}

synchronized (MyThread.class) {

total+=sum;

}

System.out.println(Thread.currentThread().getName());

latch.countDown();

}

}

}

对于CountDownLatch不熟悉的可以搜索下用法。

方式三:

通过java工具类 CyclicBarrier实现并发计算。

package test;

import java.util.concurrent.BrokenBarrierException;

import java.util.concurrent.CyclicBarrier;

public class FiveThreadCount1 {

private int[] arr={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28};

private int total=0;

public void test() throws InterruptedException, BrokenBarrierException{

int length=arr.length;

CyclicBarrier barrier=new CyclicBarrier((length%5==0?5:6)+1);

System.out.println(length);

for(int j=0;j

MyThread task;

if( (j+(length/5))<=length){

task=new MyThread(arr, j, j+(length/5), barrier);

}else{

task=new MyThread(arr, j, length, barrier);

}

new Thread(task).start();

}

barrier.await();

System.out.println(total);

}

private class MyThread implements Runnable{

int[] arr;

int startIndex;

int endIndex;

CyclicBarrier barrier;

public MyThread(int[] arr,int startIndex,int endIndex,CyclicBarrier barrier){

this.arr=arr;

this.startIndex=startIndex;

this.endIndex=endIndex;

this.barrier=barrier;

}

@Override

public void run() {

int sum=0;

for(int i=startIndex;i

sum+=arr[i];

}

synchronized (MyThread.class) {

total+=sum;

}

try {

System.out.println(Thread.currentThread().getName());

barrier.await();

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

} catch (BrokenBarrierException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

}

}

}

总结

总体来说,代码二的方式二、三,效率会高一点。以上代码都是通过main方法调用示例代码的test方法,输出结果到控制台。

sum+=arr[i];

}

System.out.println(Thread.currentThread().getName());

return sum;

}

}

}

这个方式有一个缺点,看似5个线程异步执行,其实是顺序执行,因为 task.get是要等待线程执行完毕才会执行下边的代码。所以效率不会高,可能换种写法可以解决这个问题,这里就不深入研究。

方式二:

通过java工具类CountDownLatch实现并发计算

package test;

import java.util.concurrent.CountDownLatch;

public class FiveThreadCount3 {

private int[] arr={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28};

private int total=0;

public void test() throws InterruptedException{

int length=arr.length;

CountDownLatch latch=new CountDownLatch(length%5==0?5:6);

System.out.println(length);

for(int j=0;j

MyThread task;

if( (j+(length/5))<=length){

task=new MyThread(arr, j, j+(length/5), latch);

}else{

task=new MyThread(arr, j, length, latch);

}

new Thread(task).start();

}

latch.await();

System.out.println(total);

}

private class MyThread implements Runnable{

int[] arr;

int startIndex;

int endIndex;

CountDownLatch latch;

public MyThread(int[] arr,int startIndex,int endIndex,CountDownLatch latch){

this.arr=arr;

this.startIndex=startIndex;

this.endIndex=endIndex;

this.latch=latch;

}

@Override

public void run() {

int sum=0;

for(int i=startIndex;i

sum+=arr[i];

}

synchronized (MyThread.class) {

total+=sum;

}

System.out.println(Thread.currentThread().getName());

latch.countDown();

}

}

}

对于CountDownLatch不熟悉的可以搜索下用法。

方式三:

通过java工具类 CyclicBarrier实现并发计算。

package test;

import java.util.concurrent.BrokenBarrierException;

import java.util.concurrent.CyclicBarrier;

public class FiveThreadCount1 {

private int[] arr={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28};

private int total=0;

public void test() throws InterruptedException, BrokenBarrierException{

int length=arr.length;

CyclicBarrier barrier=new CyclicBarrier((length%5==0?5:6)+1);

System.out.println(length);

for(int j=0;j

MyThread task;

if( (j+(length/5))<=length){

task=new MyThread(arr, j, j+(length/5), barrier);

}else{

task=new MyThread(arr, j, length, barrier);

}

new Thread(task).start();

}

barrier.await();

System.out.println(total);

}

private class MyThread implements Runnable{

int[] arr;

int startIndex;

int endIndex;

CyclicBarrier barrier;

public MyThread(int[] arr,int startIndex,int endIndex,CyclicBarrier barrier){

this.arr=arr;

this.startIndex=startIndex;

this.endIndex=endIndex;

this.barrier=barrier;

}

@Override

public void run() {

int sum=0;

for(int i=startIndex;i

sum+=arr[i];

}

synchronized (MyThread.class) {

total+=sum;

}

try {

System.out.println(Thread.currentThread().getName());

barrier.await();

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

} catch (BrokenBarrierException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

}

}

}

总结

总体来说,代码二的方式二、三,效率会高一点。以上代码都是通过main方法调用示例代码的test方法,输出结果到控制台。

MyThread task;

if( (j+(length/5))<=length){

task=new MyThread(arr, j, j+(length/5), latch);

}else{

task=new MyThread(arr, j, length, latch);

}

new Thread(task).start();

}

latch.await();

System.out.println(total);

}

private class MyThread implements Runnable{

int[] arr;

int startIndex;

int endIndex;

CountDownLatch latch;

public MyThread(int[] arr,int startIndex,int endIndex,CountDownLatch latch){

this.arr=arr;

this.startIndex=startIndex;

this.endIndex=endIndex;

this.latch=latch;

}

@Override

public void run() {

int sum=0;

for(int i=startIndex;i

sum+=arr[i];

}

synchronized (MyThread.class) {

total+=sum;

}

System.out.println(Thread.currentThread().getName());

latch.countDown();

}

}

}

对于CountDownLatch不熟悉的可以搜索下用法。

方式三:

通过java工具类 CyclicBarrier实现并发计算。

package test;

import java.util.concurrent.BrokenBarrierException;

import java.util.concurrent.CyclicBarrier;

public class FiveThreadCount1 {

private int[] arr={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28};

private int total=0;

public void test() throws InterruptedException, BrokenBarrierException{

int length=arr.length;

CyclicBarrier barrier=new CyclicBarrier((length%5==0?5:6)+1);

System.out.println(length);

for(int j=0;j

MyThread task;

if( (j+(length/5))<=length){

task=new MyThread(arr, j, j+(length/5), barrier);

}else{

task=new MyThread(arr, j, length, barrier);

}

new Thread(task).start();

}

barrier.await();

System.out.println(total);

}

private class MyThread implements Runnable{

int[] arr;

int startIndex;

int endIndex;

CyclicBarrier barrier;

public MyThread(int[] arr,int startIndex,int endIndex,CyclicBarrier barrier){

this.arr=arr;

this.startIndex=startIndex;

this.endIndex=endIndex;

this.barrier=barrier;

}

@Override

public void run() {

int sum=0;

for(int i=startIndex;i

sum+=arr[i];

}

synchronized (MyThread.class) {

total+=sum;

}

try {

System.out.println(Thread.currentThread().getName());

barrier.await();

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

} catch (BrokenBarrierException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

}

}

}

总结

总体来说,代码二的方式二、三,效率会高一点。以上代码都是通过main方法调用示例代码的test方法,输出结果到控制台。

sum+=arr[i];

}

synchronized (MyThread.class) {

total+=sum;

}

System.out.println(Thread.currentThread().getName());

latch.countDown();

}

}

}

对于CountDownLatch不熟悉的可以搜索下用法。

方式三:

通过java工具类 CyclicBarrier实现并发计算。

package test;

import java.util.concurrent.BrokenBarrierException;

import java.util.concurrent.CyclicBarrier;

public class FiveThreadCount1 {

private int[] arr={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28};

private int total=0;

public void test() throws InterruptedException, BrokenBarrierException{

int length=arr.length;

CyclicBarrier barrier=new CyclicBarrier((length%5==0?5:6)+1);

System.out.println(length);

for(int j=0;j

MyThread task;

if( (j+(length/5))<=length){

task=new MyThread(arr, j, j+(length/5), barrier);

}else{

task=new MyThread(arr, j, length, barrier);

}

new Thread(task).start();

}

barrier.await();

System.out.println(total);

}

private class MyThread implements Runnable{

int[] arr;

int startIndex;

int endIndex;

CyclicBarrier barrier;

public MyThread(int[] arr,int startIndex,int endIndex,CyclicBarrier barrier){

this.arr=arr;

this.startIndex=startIndex;

this.endIndex=endIndex;

this.barrier=barrier;

}

@Override

public void run() {

int sum=0;

for(int i=startIndex;i

sum+=arr[i];

}

synchronized (MyThread.class) {

total+=sum;

}

try {

System.out.println(Thread.currentThread().getName());

barrier.await();

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

} catch (BrokenBarrierException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

}

}

}

总结

总体来说,代码二的方式二、三,效率会高一点。以上代码都是通过main方法调用示例代码的test方法,输出结果到控制台。

MyThread task;

if( (j+(length/5))<=length){

task=new MyThread(arr, j, j+(length/5), barrier);

}else{

task=new MyThread(arr, j, length, barrier);

}

new Thread(task).start();

}

barrier.await();

System.out.println(total);

}

private class MyThread implements Runnable{

int[] arr;

int startIndex;

int endIndex;

CyclicBarrier barrier;

public MyThread(int[] arr,int startIndex,int endIndex,CyclicBarrier barrier){

this.arr=arr;

this.startIndex=startIndex;

this.endIndex=endIndex;

this.barrier=barrier;

}

@Override

public void run() {

int sum=0;

for(int i=startIndex;i

sum+=arr[i];

}

synchronized (MyThread.class) {

total+=sum;

}

try {

System.out.println(Thread.currentThread().getName());

barrier.await();

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

} catch (BrokenBarrierException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

}

}

}

总结

总体来说,代码二的方式二、三,效率会高一点。以上代码都是通过main方法调用示例代码的test方法,输出结果到控制台。

sum+=arr[i];

}

synchronized (MyThread.class) {

total+=sum;

}

try {

System.out.println(Thread.currentThread().getName());

barrier.await();

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

} catch (BrokenBarrierException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

}

}

}

总结

总体来说,代码二的方式二、三,效率会高一点。以上代码都是通过main方法调用示例代码的test方法,输出结果到控制台。


版权声明:本文内容由网络用户投稿,版权归原作者所有,本站不拥有其著作权,亦不承担相应法律责任。如果您发现本站中有涉嫌抄袭或描述失实的内容,请联系我们jiasou666@gmail.com 处理,核实后本网站将在24小时内删除侵权内容。

上一篇:wechall->Crypto - Digraphs writeup
下一篇:WLC2504 AP1815 客户端掉线丢包排错“日志”
相关文章

 发表评论

暂时没有评论,来抢沙发吧~