多平台统一管理软件接口,如何实现多平台统一管理软件接口
588
2022-11-04
springboot 之jpa高级查询操作
springboot的jpa可以根据方法名自动解析sql 非常方便, 只需要在 dao接口中定义方法即可;
下面是一个 demo
package com.bus365.root.dao;
import java.io.Serializable;
import java.util.List;
import org.springframework.data.jpa.repository.JpaRepository;
import org.springframework.data.jpa.repository.JpaSpecificationExecutor;
import org.springframework.data.jpa.repository.Query;
import org.springframework.data.repository.query.Param;
import com.bus365.root.model.User;
public interface UserDao extends JpaRepository
User findByName(String name);
User findByNameAndAge(String name, Integer age);
User findByNameOrAge(String name, Integer age);
/*@Query(value = "from User where name = :name")
List
}
下面展示service层调用:
@Override
public User findByName(String name) {
User user = userDao.findByName(name);
return user;
}
@Override
public User findByNameAndAge(String name, Integer age) {
User user = userDao.findByNameAndAge(name,age);
return user;
}
@Override
public User findByNameOrAge(String name, Integer age) {
User user = userDao.findByNameOrAge(name,age);
return user;
}
具体的关键字,使用方法和生产成SQL如下表所示
Keyword
Sample
JPQL snippet
And
findByLastnameAndFirstname
… where x.lastname = ?;1 and x.firstname = ?2
Or
findByLastnameOrFirstname
… where x.lastname = ?1 or x.firstname = ?2
Is,Equals
findByFirstnameIs,findByFirstnameEquals
… where x.firstname = ?1
Between
findByStartDateBetween
… where x.startDate between ?1 and ?2
LessThan
findByAgeLessThan
… where x.age < ?1
LessThanEqual
findByAgeLessThanEqual
… where x.age ⇐ ?1
GreaterThan
findByAgeGreaterThan
… where x.age > ?1
GreaterThanEqual
findByAgeGreaterThanEqual
… where x.age >= ?1
After
findByStartDateAfter
… where x.startDate > ?1
Before
findByStartDateBefore
… where x.startDate < ?1
IsNull
findByAgeIsNull
… where x.age is null
IsNotNull,NotNull
findByAge(Is)NotNull
… where x.age not null
Like
findByFirstnameLike
… where x.firstname like ?1
NotLike
findByFirstnameNotLike
… where x.firstname not like ?1
StartingWith
findByFirstnameStartingWith
… where x.firstname like ?1 (parameter bound with appended %)
EndingWith
findByFirstnameEndingWith
… where x.firstname like ?1 (parameter bound with prepended %)
Containing
findByFirstnameContaining
… where x.firstname like ?1 (parameter bound wrapped in %)
OrderBy
findByAgeOrderByLastnameDesc
… where x.age = ?1 order by x.lastname desc
Not
findByLastnameNot
… where x.lastname <> ?1
In
findByAgeIn(Collection ages)
… where x.age in ?1
NotIn
findByAgeNotIn(Collection age)
… where x.age not in ?1
TRUE
findByActiveTrue()
… where x.active = true
FALSE
findByActiveFalse()
… where x.active = false
IgnoreCase
findByFirstnameIgnoreCase
… where UPPER(x.firstame) = UPPER(?1)
下面介绍使用java原生的jpa操作数据库,对jpa熟悉的朋友应该很快就能理解,springboot使用原生jpa的关键是引入entitymanger
看一下service层
package com.bus365.root.service.impl;
import java.util.List;
import javax.persistence.EntityManager;
import javax.persistence.PersistenceContext;
import org.springframework.stereotype.Service;
import com.bus365.root.model.Address;
import com.bus365.root.service.AddressService;
@Service
public class AddressServiceImpl implements AddressService {
@PersistenceContext
private EntityManager entityManager;
public List
List resultList = entityManager.createNativeQuery("select * from address ", Address.class).getResultList();
return resultList;
}
}
注意 @PersistenceContext
private EntityManager entityManager;
动态引入entitymanger , 之后就能正常使用了;
createNativeQuery是操作原生mysql方法;支持跨表查询;
jpa的事务 直接使用注解Transactional 参数rollbackon表示回滚条件, 这个注解一搬加在service层; 注意getSingleResult 如果查不到数据会报错;
@Transactional(rollbackOn= {Exception.class})
public Address getAddressByid(Long id) {
Address singleResult = null;
try {
singleResult = (Address) entityManager
.createNativeQuery("select * from address where id = :id", Address.class).setParameter("id", id)
.getSingleResult();
} catch (Exception e) {
e.printStackTrace();
}
return singleResult;
}
jpa实现多表联查;
@Transactional
public List
List resultList = entityManager.createNativeQuery(
"select u.id id,u.age age,u.name name,a.name aname,a.completeaddress addre from user u left join address a on u.addressid = a.id where u.id = :id")
.setParameter("id", id).getResultList();
return resultList;
}
这是一个联查user 和address的例子, 返回的结果是个List
github项目地址 https://github.com/Christain1993/SpringBootIntegration
补充:springBootJpa的复杂查询
分页
/**
* 条件查询+分页
* @param whereMap
* @param page
* @param size
* @return
*/
public Page
Sort sort = new Sort(Sort.Direction.DESC,"id");
Specification
PageRequest pageRequest = new PageRequest(page,size,sort);
return caseDao.findAll(specification, pageRequest);
}
/**
* 条件查询
* @param whereMap
* @return
*/
public List
Specification
return caseDao.findAll(specification);
}
/**
* 动态条件构建
* @param searchMap
* @return
*/
private Specification
return new Specification
@Override
public Predicate toPredicate(Root
List
// 案件名称
if (searchMap.get("case_name")!=null && !"".equals(searchMap.get("case_name"))) {
predicateList.add(cb.like(root.get("case_name").as(String.class), "%"+(String)searchMap.get("case_name")+"%"));
}
// 案件编号uuid类型
ihttp://f (searchMap.get("case_uuid")!=null && !"".equals(searchMap.get("case_uuid"))) {
predicateList.add(cb.equal(root.get("case_uuid").as(String.class), (String)searchMap.get("case_uuid")));
}
return cb.and( predicateList.toArray(new Predicate[predicateList.size()]));
}
};
}
or查询
想实现这样的效果
where (state=1 or state=2)and name='zhangsan'
java代码
List
Predicate or = cb.or(cb.and(cb.equal(root.get("case_authority").as(String.class), "0")), cb.and(cb.equal(root.get("create_id").as(String.class), String.valueOf(createId))));
predicateList.add(or);
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