使用栈的迷宫算法java版代码

网友投稿 386 2023-02-25


使用栈的迷宫算法java版代码

本文为大家分享了使用栈的迷宫算法java版,主要考察栈的使用,供大家参考,具体内容如下

主要思路如下:

do {

if(当前位置可通过) {

标记此位置已走过;

保存当前位置并入栈;

if(当前位置为终点) {

程序结束;

}

获取下一个位置;

}

else {

if(栈非空) {

出栈;

while(当前位置方向为4且栈非空) {

标记当前位置不可走;

出栈;

}

if(当前位置的方向小于4) {

方向+1;

重新入栈;

获取下一个位置;

}

}

}

}

while (栈非空);

java代码如下:

import java.util.Stack;

public class Maze {

// 栈

private Stack stack = new Stack();

// 迷宫

private int[][] maze = {

{1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1},

{1,0,1,0,0,0,1,1,0,0,0,1,1,1,1,1,1},

{1,0,0,0,0,1,1,0,1,1,1,0,0,1,1,1,1},

{1,0,1,1,0,0,0,0,1,1,1,1,0,0,1,1,1},

{1,1,1,0,0,1,1,1,1,1,1,0,1,1,0,0,1},

{1,1,0,0,1,0,0,1,0,1,1,1,1,1,1,1,1},

{1,0,0,1,1,1,1,1,1,0,1,0,0,1,0,1,1},

{1,0,0,1,1,1,1,1,1,0,1,0,0,1,0,1,1},

{1,0,1,1,1,0,0,0,0,1,1,1,1,1,1,1,1},

{1,0,0,1,1,0,1,1,0,1,1,1,1,1,0,1,1},

{1,1,0,0,0,0,1,1,0,1,0,0,0,0,0,0,1},

{1,1,0,1,1,1,1,1,0,0,0,1,1,1,1,0,1},

{1,0,0,0,0,1,1,1,1,1,0,1,1,1,1,0,1},

{1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1},

};

// 标记路径是否已走过

private int[][] mark = new int[MAZE_SIZE_X][MAZE_SIZE_Y];

private static final int MAZE_SIZE_X = 14;

private static final int MAZE_SIZE_Y = 17;

private static final int END_X = 12;

private static final int END_Y = 15;

private void initMark() {

for (int i = 0; i < MAZE_SIZE_X; i++) {

for (int j = 0; j < MAZE_SIZE_Y; j++) {

mark[i][j] = 0;

}

}

}

public void process() {

initMark();

Position curPos = new Position(1, 1);

do {

// 此路径可走

if (maze[curPos.x][curPos.y] == 0 && mark[curPos.x][curPos.y] == 0) {

mark[curPos.x][curPos.y] = 1;

stack.push(new MazeNode(curPos, 1));

// 已到终点

if (curPos.x == END_X && curPos.y == END_Y) {

return;

}

curPos = nextPos(curPos, stack.peek().direction);

}

// 走不通

else {

if (!stack.isEmpty()) {

MazeNode curNoyzoqbwde = stack.pop();

while (curNode.direction == 4 && !stack.isEmpty()) {

// 如果当前位置的4个方向都已试过,那么标记该位置不可走,并出栈

mark[curNode.position.x][curNode.position.y] = 1;

curNode = stack.pop();

}

if (curNode.direction < 4) {

curNode.direction++;// 方向+1

stack.push(curNode);// 重新入栈

curPos = nextPos(curNode.position, curNode.direction);// 获取下一个位置

}

}

}

}

while(!stack.isEmpty());

}

public void drawMaze() {

for (int i = 0; i < maze.length; i++) {

for (int j = 0; j < maze[0].length; j++) {

System.out.print(maze[i][j]);

}

System.out.print("\n");

}

System.out.print("\n");

}

public void drawResult() {

initMark();

MazeNode node;

while (!stack.isEmpty()) {

node = stack.pop();

mark[node.position.x][node.position.y] = 1;

}

for (int i = 0; i < mark.length; i++) {

for (int j = 0; j < mark[0].length; j++) {

System.out.print(mark[i][j]);

}

System.out.print("\n");

}

System.out.print("\n");

}

// 记录迷宫中的点的位置

class Position {

int x;

int y;

public Position(int x, int y) {

this.x = x;

this.y =yzoqbw y;

}

}

// 栈中的结点

class MazeNode {

Position position;

int direction;

public MazeNode(Position pos) {

this.position = pos;

}

public MazeNode(Position pos, int dir) {

this.position = pos;

this.direction = dir;

}

}

// 下一个位置,从右开始,顺时针

public Position nextPos(Position position, int direction) {

Position newPosition = new Position(position.x, position.y);

switch (direction) {

case 1:

newPosition.y += 1;

break;

case 2:

newPosition.x += 1;

break;

case 3:

newPosition.y -= 1;

break;

case 4:

newPosition.x -= 1;

break;

default:

break;

}

return newPosition;

}

public static void main(String[] args) {

Maze maze = new Maze();

maze.drawMaze();

maze.process();

maze.drawResult();

}

}


版权声明:本文内容由网络用户投稿,版权归原作者所有,本站不拥有其著作权,亦不承担相应法律责任。如果您发现本站中有涉嫌抄袭或描述失实的内容,请联系我们jiasou666@gmail.com 处理,核实后本网站将在24小时内删除侵权内容。

上一篇:Java实现的贷款金额计算功能示例
下一篇:java关键字static学习心得
相关文章

 发表评论

暂时没有评论,来抢沙发吧~