java实现List中对象排序的方法

java实现List中对象排序的方法

本文实例讲述了java实现List中对象排序的方法。分享给大家供大家参考，具体如下：

package com.test;

import javoXpGKZsGla.util.ArrayList;

import java.util.Collections;

import java.util.Comparator;

import java.util.List;

public class NewsManager {

/**

* @param args

*/

public static void main(String[] args) {

List newss=getNewsList();

for(int i=0;i

{

News news=(News)newss.get(i);

System.out.println("id:"+news.getId());

System.out.println("title:"+news.getTitle());

System.out.println("hits:"+news.getHits());

}

}

public static List getNewsList()

{

List list=new ArrayList();

News news1=new News();

news1.setHits(1);

news1.setId(1);

news1.setTitle("test1");

list.add(news1);

News news2=new News();

news2.setHits(7);

news2.setId(2);

news2.setTitle("test2");

list.add(news2);

News news3=new News();

news3.setHits(3);

news3.setId(3);

news3.setTitle("test3");

list.add(news3);

News news4=new News();

news4.setHits(5);

news4.setId(4);

news4.setTitle("test4");

list.add(news4);

// 按点击数倒序

Collections.sort(list, new Comparator() {

public int compare(News arg0, News arg1) {

int hits0 = arg0.getHits();

int hits1 = arg1.getHits();

if (hits1 > hits0) {

return 1;

} else if (hits1 == hits0) {

return 0;

} else {

return -1;

}

}

});

return list;

}

}

希望本文所述对大家Java程序设计有所帮助。

{

News news=(News)newss.get(i);

System.out.println("id:"+news.getId());

System.out.println("title:"+news.getTitle());

System.out.println("hits:"+news.getHits());

}

}

public static List getNewsList()

{

List list=new ArrayList();

News news1=new News();

news1.setHits(1);

news1.setId(1);

news1.setTitle("test1");

list.add(news1);

News news2=new News();

news2.setHits(7);

news2.setId(2);

news2.setTitle("test2");

list.add(news2);

News news3=new News();

news3.setHits(3);

news3.setId(3);

news3.setTitle("test3");

list.add(news3);

News news4=new News();

news4.setHits(5);

news4.setId(4);

news4.setTitle("test4");

list.add(news4);

// 按点击数倒序

Collections.sort(list, new Comparator() {

public int compare(News arg0, News arg1) {

int hits0 = arg0.getHits();

int hits1 = arg1.getHits();

if (hits1 > hits0) {

return 1;

} else if (hits1 == hits0) {

return 0;

} else {

return -1;

}

}

});

return list;

}

}

希望本文所述对大家Java程序设计有所帮助。

版权声明：本文内容由网络用户投稿，版权归原作者所有，本站不拥有其著作权，亦不承担相应法律责任。如果您发现本站中有涉嫌抄袭或描述失实的内容，请联系我们jiasou666@gmail.com 处理，核实后本网站将在24小时内删除侵权内容。